Exam: All Exams | Subject: Quantitative Aptitude | Topic: Time & Work | Year: 2026
Time and Work is a consistently high-scoring topic in SSC exams. Problems involve workers completing tasks alone or together, pipes filling/emptying tanks, and efficiency comparisons. Master the unit approach for quick solutions.
Test your understanding of Time & Work with these All Exams level questions.
Q1. A can complete work in 12 days, B in 18 days. Together they complete in:
Explanation: A's 1-day work = 1/12, B's = 1/18. Together = 1/12 + 1/18 = 3/36 + 2/36 = 5/36. Time = 36/5 = 7.2 days.
Q2. A does 2/3 of work in 10 days. Time to complete rest:
Explanation: 2/3 of work → 10 days. Full work → 15 days. Remaining = 1/3 of work → 15 × 1/3 = 5 days.
Q3. A is twice as efficient as B. Together they finish in 14 days. B alone takes:
Explanation: A = 2B in efficiency. (A+B) = 3B. 3B does work in 14 days. B alone = 14 × 3 = 42 days.
Q4. A and B can finish a work in 30 days. B and C in 40 days, A and C in 60 days. Together:
Explanation: 2(A+B+C) = 1/30+1/40+1/60 = 4/120+3/120+2/120 = 9/120 = 3/40. A+B+C = 3/80. Time = 80/3 ≈ 26.67 days. (Standard formula approach)
Q5. A tap fills a tank in 6 hours, another empties in 9 hours. Net fill time (both open):
Explanation: Net rate = 1/6 - 1/9 = 3/18 - 2/18 = 1/18 per hour. Tank fills in 18 hours.
Q6. A can complete work in 12 days, B in 18 days. Together they complete in:
Explanation: A's 1-day work = 1/12, B's = 1/18. Together = 1/12 + 1/18 = 3/36 + 2/36 = 5/36. Time = 36/5 = 7.2 days.
Q7. A does 2/3 of work in 10 days. Time to complete rest:
Explanation: 2/3 of work → 10 days. Full work → 15 days. Remaining = 1/3 of work → 15 × 1/3 = 5 days.
Q8. A is twice as efficient as B. Together they finish in 14 days. B alone takes:
Explanation: A = 2B in efficiency. (A+B) = 3B. 3B does work in 14 days. B alone = 14 × 3 = 42 days.
Q9. A and B can finish a work in 30 days. B and C in 40 days, A and C in 60 days. Together:
Explanation: 2(A+B+C) = 1/30+1/40+1/60 = 4/120+3/120+2/120 = 9/120 = 3/40. A+B+C = 3/80. Time = 80/3 ≈ 26.67 days. (Standard formula approach)
Q10. A tap fills a tank in 6 hours, another empties in 9 hours. Net fill time (both open):
Explanation: Net rate = 1/6 - 1/9 = 3/18 - 2/18 = 1/18 per hour. Tank fills in 18 hours.
Prepared for All Exams 2026 examination by GPT Sir. Visit gptsir.in for more practice material and AI-powered study assistance.